CVE-2023-53022

In the Linux kernel, the following vulnerability has been resolved:

net: enetc: avoid deadlock in enetc_tx_onestep_tstamp()

This lockdep splat says it better than I could:

================================ WARNING: inconsistent lock state 6.2.0-rc2-07010-ga9b9500ffaac-dirty #967 Not tainted

inconsistent {IN-SOFTIRQ-W} -> {SOFTIRQ-ON-W} usage. kworker/1:3/179 [HC0[0]:SC0[0]:HE1:SE1] takes: ffff3ec4036ce098 (_xmit_ETHER#2){+.?.}-{3:3}, at: netif_freeze_queues+0x5c/0xc0 {IN-SOFTIRQ-W} state was registered at: _raw_spin_lock+0x5c/0xc0 sch_direct_xmit+0x148/0x37c __dev_queue_xmit+0x528/0x111c ip6_finish_output2+0x5ec/0xb7c ip6_finish_output+0x240/0x3f0 ip6_output+0x78/0x360 ndisc_send_skb+0x33c/0x85c ndisc_send_rs+0x54/0x12c addrconf_rs_timer+0x154/0x260 call_timer_fn+0xb8/0x3a0 __run_timers.part.0+0x214/0x26c run_timer_softirq+0x3c/0x74 __do_softirq+0x14c/0x5d8 ____do_softirq+0x10/0x20 call_on_irq_stack+0x2c/0x5c do_softirq_own_stack+0x1c/0x30 __irq_exit_rcu+0x168/0x1a0 irq_exit_rcu+0x10/0x40 el1_interrupt+0x38/0x64 irq event stamp: 7825 hardirqs last enabled at (7825): [<ffffdf1f7200cae4>] exit_to_kernel_mode+0x34/0x130 hardirqs last disabled at (7823): [<ffffdf1f708105f0>] __do_softirq+0x550/0x5d8 softirqs last enabled at (7824): [<ffffdf1f7081050c>] __do_softirq+0x46c/0x5d8 softirqs last disabled at (7811): [<ffffdf1f708166e0>] ____do_softirq+0x10/0x20

other info that might help us debug this: Possible unsafe locking scenario:

   CPU0
   ----

lock(_xmit_ETHER#2); <Interrupt> lock(_xmit_ETHER#2);

*** DEADLOCK ***

3 locks held by kworker/1:3/179: #0: ffff3ec400004748 ((wq_completion)events){+.+.}-{0:0}, at: process_one_work+0x1f4/0x6c0 #1: ffff80000a0bbdc8 ((work_completion)(&priv->tx_onestep_tstamp)){+.+.}-{0:0}, at: process_one_work+0x1f4/0x6c0 #2: ffff3ec4036cd438 (&dev->tx_global_lock){+.+.}-{3:3}, at: netif_tx_lock+0x1c/0x34

Workqueue: events enetc_tx_onestep_tstamp Call trace: print_usage_bug.part.0+0x208/0x22c mark_lock+0x7f0/0x8b0 __lock_acquire+0x7c4/0x1ce0 lock_acquire.part.0+0xe0/0x220 lock_acquire+0x68/0x84 _raw_spin_lock+0x5c/0xc0 netif_freeze_queues+0x5c/0xc0 netif_tx_lock+0x24/0x34 enetc_tx_onestep_tstamp+0x20/0x100 process_one_work+0x28c/0x6c0 worker_thread+0x74/0x450 kthread+0x118/0x11c

but I'll say it anyway: the enetc_tx_onestep_tstamp() work item runs in process context, therefore with softirqs enabled (i.o.w., it can be interrupted by a softirq). If we hold the netif_tx_lock() when there is an interrupt, and the NET_TX softirq then gets scheduled, this will take the netif_tx_lock() a second time and deadlock the kernel.

To solve this, use netif_tx_lock_bh(), which blocks softirqs from running.

In the Linux kernel, the following vulnerability has been resolved:

net: enetc: avoid deadlock in enetc_tx_onestep_tstamp()

This lockdep splat says it better than I could:

================================ WARNING: inconsistent lock state 6.2.0-rc2-07010-ga9b9500ffaac-dirty #967 Not tainted

inconsistent {IN-SOFTIRQ-W} -> {SOFTIRQ-ON-W} usage. kworker/1:3/179 [HC0[0]:SC0[0]:HE1:SE1] takes: ffff3ec4036ce098 (_xmit_ETHER#2){+.?.}-{3:3}, at: netif_freeze_queues+0x5c/0xc0 {IN-SOFTIRQ-W} state was registered at: _raw_spin_lock+0x5c/0xc0 sch_direct_xmit+0x148/0x37c __dev_queue_xmit+0x528/0x111c ip6_finish_output2+0x5ec/0xb7c ip6_finish_output+0x240/0x3f0 ip6_output+0x78/0x360 ndisc_send_skb+0x33c/0x85c ndisc_send_rs+0x54/0x12c addrconf_rs_timer+0x154/0x260 call_timer_fn+0xb8/0x3a0 __run_timers.part.0+0x214/0x26c run_timer_softirq+0x3c/0x74 __do_softirq+0x14c/0x5d8 ____do_softirq+0x10/0x20 call_on_irq_stack+0x2c/0x5c do_softirq_own_stack+0x1c/0x30 __irq_exit_rcu+0x168/0x1a0 irq_exit_rcu+0x10/0x40 el1_interrupt+0x38/0x64 irq event stamp: 7825 hardirqs last enabled at (7825): [<ffffdf1f7200cae4>] exit_to_kernel_mode+0x34/0x130 hardirqs last disabled at (7823): [<ffffdf1f708105f0>] __do_softirq+0x550/0x5d8 softirqs last enabled at (7824): [<ffffdf1f7081050c>] __do_softirq+0x46c/0x5d8 softirqs last disabled at (7811): [<ffffdf1f708166e0>] ____do_softirq+0x10/0x20

other info that might help us debug this: Possible unsafe locking scenario:

   CPU0
   ----

lock(_xmit_ETHER#2); <Interrupt> lock(_xmit_ETHER#2);

*** DEADLOCK ***

3 locks held by kworker/1:3/179: #0: ffff3ec400004748 ((wq_completion)events){+.+.}-{0:0}, at: process_one_work+0x1f4/0x6c0 #1: ffff80000a0bbdc8 ((work_completion)(&priv->tx_onestep_tstamp)){+.+.}-{0:0}, at: process_one_work+0x1f4/0x6c0 #2: ffff3ec4036cd438 (&dev->tx_global_lock){+.+.}-{3:3}, at: netif_tx_lock+0x1c/0x34

Workqueue: events enetc_tx_onestep_tstamp Call trace: print_usage_bug.part.0+0x208/0x22c mark_lock+0x7f0/0x8b0 __lock_acquire+0x7c4/0x1ce0 lock_acquire.part.0+0xe0/0x220 lock_acquire+0x68/0x84 _raw_spin_lock+0x5c/0xc0 netif_freeze_queues+0x5c/0xc0 netif_tx_lock+0x24/0x34 enetc_tx_onestep_tstamp+0x20/0x100 process_one_work+0x28c/0x6c0 worker_thread+0x74/0x450 kthread+0x118/0x11c

but I'll say it anyway: the enetc_tx_onestep_tstamp() work item runs in process context, therefore with softirqs enabled (i.o.w., it can be interrupted by a softirq). If we hold the netif_tx_lock() when there is an interrupt, and the NET_TX softirq then gets scheduled, this will take the netif_tx_lock() a second time and deadlock the kernel.

To solve this, use netif_tx_lock_bh(), which blocks softirqs from running.

In the Linux kernel, the following vulnerability has been resolved:

net: enetc: avoid deadlock in enetc_tx_onestep_tstamp()

This lockdep splat says it better than I could:

================================ WARNING: inconsistent lock state 6.2.0-rc2-07010-ga9b9500ffaac-dirty #967 Not tainted

inconsistent {IN-SOFTIRQ-W} -> {SOFTIRQ-ON-W} usage. kworker/1:3/179 [HC0[0]:SC0[0]:HE1:SE1] takes: ffff3ec4036ce098 (_xmit_ETHER#2){+.?.}-{3:3}, at: netif_freeze_queues+0x5c/0xc0 {IN-SOFTIRQ-W} state was registered at: _raw_spin_lock+0x5c/0xc0 sch_direct_xmit+0x148/0x37c __dev_queue_xmit+0x528/0x111c ip6_finish_output2+0x5ec/0xb7c ip6_finish_output+0x240/0x3f0 ip6_output+0x78/0x360 ndisc_send_skb+0x33c/0x85c ndisc_send_rs+0x54/0x12c addrconf_rs_timer+0x154/0x260 call_timer_fn+0xb8/0x3a0 __run_timers.part.0+0x214/0x26c run_timer_softirq+0x3c/0x74 __do_softirq+0x14c/0x5d8 ____do_softirq+0x10/0x20 call_on_irq_stack+0x2c/0x5c do_softirq_own_stack+0x1c/0x30 __irq_exit_rcu+0x168/0x1a0 irq_exit_rcu+0x10/0x40 el1_interrupt+0x38/0x64 irq event stamp: 7825 hardirqs last enabled at (7825): [<ffffdf1f7200cae4>] exit_to_kernel_mode+0x34/0x130 hardirqs last disabled at (7823): [<ffffdf1f708105f0>] __do_softirq+0x550/0x5d8 softirqs last enabled at (7824): [<ffffdf1f7081050c>] __do_softirq+0x46c/0x5d8 softirqs last disabled at (7811): [<ffffdf1f708166e0>] ____do_softirq+0x10/0x20

other info that might help us debug this: Possible unsafe locking scenario:

   CPU0
   ----

lock(_xmit_ETHER#2); <Interrupt> lock(_xmit_ETHER#2);

*** DEADLOCK ***

3 locks held by kworker/1:3/179: #0: ffff3ec400004748 ((wq_completion)events){+.+.}-{0:0}, at: process_one_work+0x1f4/0x6c0 #1: ffff80000a0bbdc8 ((work_completion)(&priv->tx_onestep_tstamp)){+.+.}-{0:0}, at: process_one_work+0x1f4/0x6c0 #2: ffff3ec4036cd438 (&dev->tx_global_lock){+.+.}-{3:3}, at: netif_tx_lock+0x1c/0x34

Workqueue: events enetc_tx_onestep_tstamp Call trace: print_usage_bug.part.0+0x208/0x22c mark_lock+0x7f0/0x8b0 __lock_acquire+0x7c4/0x1ce0 lock_acquire.part.0+0xe0/0x220 lock_acquire+0x68/0x84 _raw_spin_lock+0x5c/0xc0 netif_freeze_queues+0x5c/0xc0 netif_tx_lock+0x24/0x34 enetc_tx_onestep_tstamp+0x20/0x100 process_one_work+0x28c/0x6c0 worker_thread+0x74/0x450 kthread+0x118/0x11c

but I'll say it anyway: the enetc_tx_onestep_tstamp() work item runs in process context, therefore with softirqs enabled (i.o.w., it can be interrupted by a softirq). If we hold the netif_tx_lock() when there is an interrupt, and the NET_TX softirq then gets scheduled, this will take the netif_tx_lock() a second time and deadlock the kernel.

To solve this, use netif_tx_lock_bh(), which blocks softirqs from running.

In the Linux kernel, the following vulnerability has been resolved:

net: enetc: avoid deadlock in enetc_tx_onestep_tstamp()

This lockdep splat says it better than I could:

================================ WARNING: inconsistent lock state 6.2.0-rc2-07010-ga9b9500ffaac-dirty #967 Not tainted

inconsistent {IN-SOFTIRQ-W} -> {SOFTIRQ-ON-W} usage. kworker/1:3/179 [HC0[0]:SC0[0]:HE1:SE1] takes: ffff3ec4036ce098 (_xmit_ETHER#2){+.?.}-{3:3}, at: netif_freeze_queues+0x5c/0xc0 {IN-SOFTIRQ-W} state was registered at: _raw_spin_lock+0x5c/0xc0 sch_direct_xmit+0x148/0x37c __dev_queue_xmit+0x528/0x111c ip6_finish_output2+0x5ec/0xb7c ip6_finish_output+0x240/0x3f0 ip6_output+0x78/0x360 ndisc_send_skb+0x33c/0x85c ndisc_send_rs+0x54/0x12c addrconf_rs_timer+0x154/0x260 call_timer_fn+0xb8/0x3a0 __run_timers.part.0+0x214/0x26c run_timer_softirq+0x3c/0x74 __do_softirq+0x14c/0x5d8 ____do_softirq+0x10/0x20 call_on_irq_stack+0x2c/0x5c do_softirq_own_stack+0x1c/0x30 __irq_exit_rcu+0x168/0x1a0 irq_exit_rcu+0x10/0x40 el1_interrupt+0x38/0x64 irq event stamp: 7825 hardirqs last enabled at (7825): [<ffffdf1f7200cae4>] exit_to_kernel_mode+0x34/0x130 hardirqs last disabled at (7823): [<ffffdf1f708105f0>] __do_softirq+0x550/0x5d8 softirqs last enabled at (7824): [<ffffdf1f7081050c>] __do_softirq+0x46c/0x5d8 softirqs last disabled at (7811): [<ffffdf1f708166e0>] ____do_softirq+0x10/0x20

other info that might help us debug this: Possible unsafe locking scenario:

   CPU0
   ----

lock(_xmit_ETHER#2); <Interrupt> lock(_xmit_ETHER#2);

*** DEADLOCK ***

3 locks held by kworker/1:3/179: #0: ffff3ec400004748 ((wq_completion)events){+.+.}-{0:0}, at: process_one_work+0x1f4/0x6c0 #1: ffff80000a0bbdc8 ((work_completion)(&priv->tx_onestep_tstamp)){+.+.}-{0:0}, at: process_one_work+0x1f4/0x6c0 #2: ffff3ec4036cd438 (&dev->tx_global_lock){+.+.}-{3:3}, at: netif_tx_lock+0x1c/0x34

Workqueue: events enetc_tx_onestep_tstamp Call trace: print_usage_bug.part.0+0x208/0x22c mark_lock+0x7f0/0x8b0 __lock_acquire+0x7c4/0x1ce0 lock_acquire.part.0+0xe0/0x220 lock_acquire+0x68/0x84 _raw_spin_lock+0x5c/0xc0 netif_freeze_queues+0x5c/0xc0 netif_tx_lock+0x24/0x34 enetc_tx_onestep_tstamp+0x20/0x100 process_one_work+0x28c/0x6c0 worker_thread+0x74/0x450 kthread+0x118/0x11c

but I'll say it anyway: the enetc_tx_onestep_tstamp() work item runs in process context, therefore with softirqs enabled (i.o.w., it can be interrupted by a softirq). If we hold the netif_tx_lock() when there is an interrupt, and the NET_TX softirq then gets scheduled, this will take the netif_tx_lock() a second time and deadlock the kernel.

To solve this, use netif_tx_lock_bh(), which blocks softirqs from running.

In the Linux kernel, the following vulnerability has been resolved:

net: enetc: avoid deadlock in enetc_tx_onestep_tstamp()

This lockdep splat says it better than I could:

================================ WARNING: inconsistent lock state 6.2.0-rc2-07010-ga9b9500ffaac-dirty #967 Not tainted

inconsistent {IN-SOFTIRQ-W} -> {SOFTIRQ-ON-W} usage. kworker/1:3/179 [HC0[0]:SC0[0]:HE1:SE1] takes: ffff3ec4036ce098 (_xmit_ETHER#2){+.?.}-{3:3}, at: netif_freeze_queues+0x5c/0xc0 {IN-SOFTIRQ-W} state was registered at: _raw_spin_lock+0x5c/0xc0 sch_direct_xmit+0x148/0x37c __dev_queue_xmit+0x528/0x111c ip6_finish_output2+0x5ec/0xb7c ip6_finish_output+0x240/0x3f0 ip6_output+0x78/0x360 ndisc_send_skb+0x33c/0x85c ndisc_send_rs+0x54/0x12c addrconf_rs_timer+0x154/0x260 call_timer_fn+0xb8/0x3a0 __run_timers.part.0+0x214/0x26c run_timer_softirq+0x3c/0x74 __do_softirq+0x14c/0x5d8 ____do_softirq+0x10/0x20 call_on_irq_stack+0x2c/0x5c do_softirq_own_stack+0x1c/0x30 __irq_exit_rcu+0x168/0x1a0 irq_exit_rcu+0x10/0x40 el1_interrupt+0x38/0x64 irq event stamp: 7825 hardirqs last enabled at (7825): [<ffffdf1f7200cae4>] exit_to_kernel_mode+0x34/0x130 hardirqs last disabled at (7823): [<ffffdf1f708105f0>] __do_softirq+0x550/0x5d8 softirqs last enabled at (7824): [<ffffdf1f7081050c>] __do_softirq+0x46c/0x5d8 softirqs last disabled at (7811): [<ffffdf1f708166e0>] ____do_softirq+0x10/0x20

other info that might help us debug this: Possible unsafe locking scenario:

   CPU0
   ----

lock(_xmit_ETHER#2); <Interrupt> lock(_xmit_ETHER#2);

*** DEADLOCK ***

3 locks held by kworker/1:3/179: #0: ffff3ec400004748 ((wq_completion)events){+.+.}-{0:0}, at: process_one_work+0x1f4/0x6c0 #1: ffff80000a0bbdc8 ((work_completion)(&priv->tx_onestep_tstamp)){+.+.}-{0:0}, at: process_one_work+0x1f4/0x6c0 #2: ffff3ec4036cd438 (&dev->tx_global_lock){+.+.}-{3:3}, at: netif_tx_lock+0x1c/0x34

Workqueue: events enetc_tx_onestep_tstamp Call trace: print_usage_bug.part.0+0x208/0x22c mark_lock+0x7f0/0x8b0 __lock_acquire+0x7c4/0x1ce0 lock_acquire.part.0+0xe0/0x220 lock_acquire+0x68/0x84 _raw_spin_lock+0x5c/0xc0 netif_freeze_queues+0x5c/0xc0 netif_tx_lock+0x24/0x34 enetc_tx_onestep_tstamp+0x20/0x100 process_one_work+0x28c/0x6c0 worker_thread+0x74/0x450 kthread+0x118/0x11c

but I'll say it anyway: the enetc_tx_onestep_tstamp() work item runs in process context, therefore with softirqs enabled (i.o.w., it can be interrupted by a softirq). If we hold the netif_tx_lock() when there is an interrupt, and the NET_TX softirq then gets scheduled, this will take the netif_tx_lock() a second time and deadlock the kernel.

To solve this, use netif_tx_lock_bh(), which blocks softirqs from running.

In the Linux kernel, the following vulnerability has been resolved: net: enetc: avoid deadlock in enetc_tx_onestep_tstamp() This lockdep splat says it better than I could: ================================ WARNING: inconsistent lock state 6.2.0-rc2-07010-ga9b9500ffaac-dirty #967 Not tainted -------------------------------- inconsistent {IN-SOFTIRQ-W} -> {SOFTIRQ-ON-W} usage. kworker/1:3/179 [HC0[0]:SC0[0]:HE1:SE1] takes: ffff3ec4036ce098 (_xmit_ETHER#2){+.?.}-{3:3}, at: netif_freeze_queues+0x5c/0xc0 {IN-SOFTIRQ-W} state was registered at: _raw_spin_lock+0x5c/0xc0 sch_direct_xmit+0x148/0x37c __dev_queue_xmit+0x528/0x111c ip6_finish_output2+0x5ec/0xb7c ip6_finish_output+0x240/0x3f0 ip6_output+0x78/0x360 ndisc_send_skb+0x33c/0x85c ndisc_send_rs+0x54/0x12c addrconf_rs_timer+0x154/0x260 call_timer_fn+0xb8/0x3a0 __run_timers.part.0+0x214/0x26c run_timer_softirq+0x3c/0x74 __do_softirq+0x14c/0x5d8 ____do_softirq+0x10/0x20 call_on_irq_stack+0x2c/0x5c do_softirq_own_stack+0x1c/0x30 __irq_exit_rcu+0x168/0x1a0 irq_exit_rcu+0x10/0x40 el1_interrupt+0x38/0x64 irq event stamp: 7825 hardirqs last enabled at (7825): [<ffffdf1f7200cae4>] exit_to_kernel_mode+0x34/0x130 hardirqs last disabled at (7823): [<ffffdf1f708105f0>] __do_softirq+0x550/0x5d8 softirqs last enabled at (7824): [<ffffdf1f7081050c>] __do_softirq+0x46c/0x5d8 softirqs last disabled at (7811): [<ffffdf1f708166e0>] ____do_softirq+0x10/0x20 other info that might help us debug this: Possible unsafe locking scenario: CPU0 ---- lock(_xmit_ETHER#2); <Interrupt> lock(_xmit_ETHER#2); *** DEADLOCK *** 3 locks held by kworker/1:3/179: #0: ffff3ec400004748 ((wq_completion)events){+.+.}-{0:0}, at: process_one_work+0x1f4/0x6c0 #1: ffff80000a0bbdc8 ((work_completion)(&priv->tx_onestep_tstamp)){+.+.}-{0:0}, at: process_one_work+0x1f4/0x6c0 #2: ffff3ec4036cd438 (&dev->tx_global_lock){+.+.}-{3:3}, at: netif_tx_lock+0x1c/0x34 Workqueue: events enetc_tx_onestep_tstamp Call trace: print_usage_bug.part.0+0x208/0x22c mark_lock+0x7f0/0x8b0 __lock_acquire+0x7c4/0x1ce0 lock_acquire.part.0+0xe0/0x220 lock_acquire+0x68/0x84 _raw_spin_lock+0x5c/0xc0 netif_freeze_queues+0x5c/0xc0 netif_tx_lock+0x24/0x34 enetc_tx_onestep_tstamp+0x20/0x100 process_one_work+0x28c/0x6c0 worker_thread+0x74/0x450 kthread+0x118/0x11c but I'll say it anyway: the enetc_tx_onestep_tstamp() work item runs in process context, therefore with softirqs enabled (i.o.w., it can be interrupted by a softirq). If we hold the netif_tx_lock() when there is an interrupt, and the NET_TX softirq then gets scheduled, this will take the netif_tx_lock() a second time and deadlock the kernel. To solve this, use netif_tx_lock_bh(), which blocks softirqs from running.

In the Linux kernel, the following vulnerability has been resolved: net: enetc: avoid deadlock in enetc_tx_onestep_tstamp() This lockdep splat says it better than I could: ================================ WARNING: inconsistent lock state 6.2.0-rc2-07010-ga9b9500ffaac-dirty #967 Not tainted -------------------------------- inconsistent {IN-SOFTIRQ-W} -> {SOFTIRQ-ON-W} usage. kworker/1:3/179 [HC0[0]:SC0[0]:HE1:SE1] takes: ffff3ec4036ce098 (_xmit_ETHER#2){+.?.}-{3:3}, at: netif_freeze_queues+0x5c/0xc0 {IN-SOFTIRQ-W} state was registered at: _raw_spin_lock+0x5c/0xc0 sch_direct_xmit+0x148/0x37c __dev_queue_xmit+0x528/0x111c ip6_finish_output2+0x5ec/0xb7c ip6_finish_output+0x240/0x3f0 ip6_output+0x78/0x360 ndisc_send_skb+0x33c/0x85c ndisc_send_rs+0x54/0x12c addrconf_rs_timer+0x154/0x260 call_timer_fn+0xb8/0x3a0 __run_timers.part.0+0x214/0x26c run_timer_softirq+0x3c/0x74 __do_softirq+0x14c/0x5d8 ____do_softirq+0x10/0x20 call_on_irq_stack+0x2c/0x5c do_softirq_own_stack+0x1c/0x30 __irq_exit_rcu+0x168/0x1a0 irq_exit_rcu+0x10/0x40 el1_interrupt+0x38/0x64 irq event stamp: 7825 hardirqs last enabled at (7825): [<ffffdf1f7200cae4>] exit_to_kernel_mode+0x34/0x130 hardirqs last disabled at (7823): [<ffffdf1f708105f0>] __do_softirq+0x550/0x5d8 softirqs last enabled at (7824): [<ffffdf1f7081050c>] __do_softirq+0x46c/0x5d8 softirqs last disabled at (7811): [<ffffdf1f708166e0>] ____do_softirq+0x10/0x20 other info that might help us debug this: Possible unsafe locking scenario: CPU0 ---- lock(_xmit_ETHER#2); <Interrupt> lock(_xmit_ETHER#2); *** DEADLOCK *** 3 locks held by kworker/1:3/179: #0: ffff3ec400004748 ((wq_completion)events){+.+.}-{0:0}, at: process_one_work+0x1f4/0x6c0 #1: ffff80000a0bbdc8 ((work_completion)(&priv->tx_onestep_tstamp)){+.+.}-{0:0}, at: process_one_work+0x1f4/0x6c0 #2: ffff3ec4036cd438 (&dev->tx_global_lock){+.+.}-{3:3}, at: netif_tx_lock+0x1c/0x34 Workqueue: events enetc_tx_onestep_tstamp Call trace: print_usage_bug.part.0+0x208/0x22c mark_lock+0x7f0/0x8b0 __lock_acquire+0x7c4/0x1ce0 lock_acquire.part.0+0xe0/0x220 lock_acquire+0x68/0x84 _raw_spin_lock+0x5c/0xc0 netif_freeze_queues+0x5c/0xc0 netif_tx_lock+0x24/0x34 enetc_tx_onestep_tstamp+0x20/0x100 process_one_work+0x28c/0x6c0 worker_thread+0x74/0x450 kthread+0x118/0x11c but I'll say it anyway: the enetc_tx_onestep_tstamp() work item runs in process context, therefore with softirqs enabled (i.o.w., it can be interrupted by a softirq). If we hold the netif_tx_lock() when there is an interrupt, and the NET_TX softirq then gets scheduled, this will take the netif_tx_lock() a second time and deadlock the kernel. To solve this, use netif_tx_lock_bh(), which blocks softirqs from running.